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GRE·94-4考题-4

时间:2021-09-06 16:12:26 其它考试 我要投稿

GRE·94-4考题-(4)

 Seven chimpanzees—G, H, K, L, N, P, and Q—are to be

GRE·94-4考题-(4)

assigned to four observer—Richards, Smith, Torres,

and Yang-with each chimpanzee assigned to exactly one

observer and each observer assigned at most two chim-

panzees. P and Q are juveniles: the other five chim-

panzees are adults. G, H, and P are male: the other

four chimpanzees are female. The following conditions

govern the assignment of the chimpanzees to the observers:

 Only male chimpanzees can be assigned to Richards.

 At most one chimpanzee can be assigned to Smith.

 Whenever a juvenile is assigned to an observer, an

  adult chimpanzee of the same sex as the juvenile

  must also be assigned to that observer.

Which of the following represents an acceptable assignment of the

chimpanzees to the observers?

      Richards  Smith Torres Yang        

G,P H K,L,Q N

G,P H L,Q K, N     

G,P L K,N H, Q

H,L K N,Q G, P

H,P G,K N,Q L

————————————————————————

答案:(B)

读题:7只黑猩猩,G、H、K、L、N、P、Q,分配给4个观察者,R、S、T、Y,每只猩猩都要分配

  给一个人,每个人最多2只猩猩。

    

写条件:

1、R:male (表示只有雄性猩猩才能给R)

2、S≤1 (表示S最多只分配一只猩猩)

3、one juv→one adult(same sex) (表示如果一只未成年的猩猩分配给观察者,

那么同性的一只成年猩猩必须分配给那个观察者)

  

条件总结:

  1、4个观察者我们可以看为四组,7个元素分为四组,那么首先注意数字分配关系

   题目中有每组最多2只猩猩,则分配关系为(2、2、2、1)

   而条件2告诉我们,S≤1,所以R,T,Y各有2个元素

  

  2、上面的条件3不涉及具体元素,我们看是否能和被它限制的元素结合起来。

  如果一只未成年的猩猩分配给观察者,那么同性的一只成年猩猩必须分配给那个观察

  者,显然限制是对未成年猩猩而言,题目中有两个元素属于未成年猩猩, P,Q,因此

  得到:

  P+(G/H中选择一个)

  Q+(K/L/N三者中选择一个)

   

题目中一共只有3只雄性猩猩,而条件1告诉我们R中就必须要有两只雄性猩猩,

因此R中的元素必然为  P+(G/H中选择一个)

  

分析到此,整个题组以完全在你的掌握之中,而我们所用的方法还是我们经常讲的

 

Which of the following must be true?

H is assigned to Smith.

K is assigned to Yang

L is assigned to Torres.

P is assigned to Richards.

Q is assigned to Torres.

————————————————————————

答案:(D)

读题:7只黑猩猩,G、H、K、L、N、P、Q,分配给4个观察者,R、S