位域的规律题
有无unsigned、a:1 a:2 a:4 a:8 a:16 a:32 以及用char的各值来试验就可发现位域的.规律,
位域的规律题
。#include <iostream>
#include <windows.h>
using namespace std;
void main()
{
struct test
{
//在这里测试就可以发现其规律,有无unsigned、a:1 a:2 a:4 a:8 a:16 a:32 以及用char的各值来试验就可发现位域的规律
unsigned int a:8;
};
test t1;
t1.a = 0;
cout<<"十进制 -> 0: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 0: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 1;
cout<<"十进制 -> 1: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 1: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 2;
cout<<"十进制 -> 2: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 2: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 3;
cout<<"十进制 -> 3: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 3: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 126;
cout<<"十进制 -> 126: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 126: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 127;
cout<<"十进制 -> 127: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 127: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 128;
cout<<"十进制 -> 128: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 128: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 129;
cout<<"十进制 -> 129: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 129: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 253;
cout<<"十进制 -> 253: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 253: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 254;
cout<<"十进制 -> 254: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 254: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 255;
cout<<"十进制 -> 255: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 255: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 256;
cout<<"十进制 -> 256: "<<dec<<t1.a<<endl;
cout<<"十六进制-> 256: "<<hex<<t1.a<<endl;
cout<<endl;
t1.a = 257;
【位域的规律题】相关文章:
1.职场生存规律
4.职业规划中的规律
6.4条学习规律